Jak na moje to:
1. Spoko
Ca(OH)2 <--> Ca^2+ + 2OH^-
więc [OH]= 2* 0,00005= 0,0001
pOH= -log[OH] = 4
Pkw= pOH + pH
14= 4 + x
x= 10
4.
Cm=n/V
n= 0,05 mol
0,05 mol = 1,825 gram
Cp= ms/mr *100%
36%= 1,825/mr *100%
mr= (1,825*100%)/36%
mr= 5,1 g
d= M/V
V=M/d
V= 5,1/1,18
V= 4, 32 cm^3
2 nie...